你最愿意做的哪件事,才是你的天赋所在

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HDU4614-线段树

题目链接

HDU4614

思路

首先建好线段树,功能是删除连续的1,查询区间和,插入1.就够了
然后二分找出起点,再二分找出终点即可。
注意的是,线段树lazy标记一定要注意两者之间的逻辑关系。

代码实现

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#include<bits/stdc++.h>
using namespace std;
const int N =5e4+10;
#define lson l,mid,rt<<1
#define rson mid+1,r,rt<<1|1
int n,m;
struct node
{
int l,r;
int val;
bool put;
bool in;
int len()
{
return r-l+1;
}
}tree[N<<2];
void PushUp(int rt)
{
tree[rt].val=(tree[rt<<1].val+tree[rt<<1|1].val);
}
void PushDown(int rt)
{
if(tree[rt].put)
{
tree[rt<<1].put=tree[rt<<1|1].put=tree[rt].put;
tree[rt<<1].in=tree[rt<<1|1].in=false;
tree[rt<<1|1].val=tree[rt<<1].val=0;
tree[rt].put=0;
}
if(tree[rt].in)
{
tree[rt<<1].in=tree[rt<<1|1].in=tree[rt].in;
tree[rt<<1].put=tree[rt<<1|1].put=false;
tree[rt<<1].val=tree[rt<<1].len();
tree[rt<<1|1].val=tree[rt<<1|1].len();
tree[rt].in=0;
}
}
void build(int l,int r,int rt)
{
tree[rt].l=l;
tree[rt].r=r;
tree[rt].val=0;
tree[rt].put=tree[rt].in=false;
if(l==r)
{
tree[rt].val=0;
return ;
}
int mid = (l+r)>>1;
build(lson);
build(rson);
PushUp(rt);
}
void Update(int rt,int l,int r)
{
if(tree[rt].r<l||tree[rt].l>r)return ;
if(tree[rt].l>=l&&tree[rt].r<=r)
{
tree[rt].put=0;
tree[rt].in=1;
tree[rt].val=tree[rt].len();
return ;
}
PushDown(rt);
Update(rt<<1,l,r);
Update(rt<<1|1,l,r);
PushUp(rt);
}
void clear(int rt,int l,int r)
{
if(tree[rt].r<l||tree[rt].l>r)return ;
if(tree[rt].l>=l&&tree[rt].r<=r)
{
tree[rt].put=1;
tree[rt].in=0;
tree[rt].val=0;
return ;
}
PushDown(rt);
clear(rt<<1,l,r);
clear(rt<<1|1,l,r);
PushUp(rt);
}
int query(int rt,int l,int r)
{
if(tree[rt].r<l||tree[rt].l>r)return 0;
int ans = 0;
if(tree[rt].l>=l&&tree[rt].r<=r)
{
return tree[rt].val;
}
PushDown(rt);
ans+=query(rt<<1,l,r);
ans+=query(rt<<1|1,l,r);
return ans;
}
int bin(int s,int rank)//rank:需要插入的花的数目
{
int l = s;
int r = n;
int ans = -1;
int mid;
while(l <= r)
{
int mid = (l + r)>>1;
int tmp = query(1,s,mid);
if(tmp + rank == mid - s + 1)
{
ans = mid;
r = mid - 1;
}
else
{
if(tmp + rank < mid - s + 1)
r = mid - 1;
else
l = mid + 1;
}
}
return ans;
}
int main()
{
int t;
scanf("%d",&t);
while(t--)
{
scanf("%d %d",&n,&m);
build(1,n,1);
while(m--)
{
int k,a,b;
scanf("%d %d %d",&k,&a,&b);
if(k==1&&a==2&&b==3)
{
k=1;
}
if(k==1)
{ a++;
a=bin(a,1);
if(a==-1)printf("Can not put any one.\n");
else{
int tem = query(1,a,n);
tem = n-a+1-tem;
if(b>=tem)
b=tem;
int res = bin(a,b);
printf("%d %d\n",a-1,res-1);
Update(1,a,res);
}
}
else
{
a++,b++;
printf("%d\n",query(1,a,b));
clear(1,a,b);
}
}
printf("\n");
}
}
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